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In this problem, we are given a number n that denotes the nth term of the series. Our task is to create a program to find the N-th term of series 7, 21, 49, 91, 147, 217, …… in C++.

**Problem Description** - We will find the nth term of the series 7, 21, 49, 91, 147, 217, … and for that, we will deduce the general term of the series.

**Let’s take an example to understand the problem,**

**Input** − N = 5

**Output** − 147

Let’s deduce the general term of the given series. The series is −

7, 21, 49, 91, 147, 217, …

We can see that 7 is common here,

7 * (1, 3, 7, 13, 21, 31, ...)

Here, we can observe that this series is increasing like a square series. So,

Series: 7 * (12 , (22 - 1), (33 - 2), (42 - 3), (52 - 4), (62 - 5), ....)

The general term of the series can be generalized as −

Tn = 7*(n2 - (n-1))

Using the general term formula, we can find any value of the series.

**For example,**

T_{4}= 7*((4^2) - (4-1)) = 7(16 - 3) = 91 T_{7}= 7*((7^2) - (7-1)) = 7(49 - 6) = 301

#include <iostream> using namespace std; int findNTerm(int N) { int nthTerm = ( 7*((N*N) - (N - 1)) ); return nthTerm; } int main() { int N = 9; cout<<N<<"th term of the series is "<<findNTerm(N); return 0; }

9th term of the series is 511

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